Kirchhoff Voltage Law states that ''The algebraic sum of all
voltages (source voltage and voltage drops) is equal to zero around a
close path''.
In the above circuit R1, R2 and R3 are three resistors connected in series across a voltage source V. VI , V2 and V3 are voltage drops across resistors R1, R2 and R3 respectively. So according to Kirchhoff voltage law
V + ( -V1 ) + ( -V2 ) + ( -V3 ) = 0
V - V1 - V2 - V3 = 0
V = VI + V2 + V3
This is called KVL ( Kirchhoff Voltage Law) equation.
V = VI + V2 + V3
Applied voltage = sum of all voltage drops
OR
The source voltage is equal to the sum of all voltage drops.
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